9p^2+33p+30=0

Solution for 9p^2+33p+30=0 equation:

9p^2+33p+30=0

a = 9; b = 33; c = +30;
Δ = b2-4ac
Δ = 332-4·9·30
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-3}{2*9}=\frac{-36}{18}
=-2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+3}{2*9}=\frac{-30}{18}
=-1+2/3
$